Let O(0,0),P(3,4),Q(6,0) be the vertices of the triangle OPQ. The point R inside the tringle OPQ is such that the triangles OPR, PQR, OQR are of equal area. The coordinates of R are
A
(43,3)
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B
(3,23)
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C
(3,43)
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D
(43,23)
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Solution
The correct option is C(3,43) ∵Ar(ΔOPR)=Ar(ΔPQR)=Ar(ΔOQR)
∴ by simply geometry Rshould be the centroid of ΔPQO ⇒R(3+6+03,4+0+03)=(3,43)