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Question

Let a and b are two non-zero, non-collinear vectors (|a|=1) such that vectors 3(a×b) and 2(b(a.b)a) represents two sides of a triangle. If area of triangle is 34(|b|4+4) then the value of |b|2 is

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Solution

v1=3(a×b)
v2=2(b(a.b)a)
v1.v2=0
|v1|=3|a||b|sinθ
|v2|=2(b(a.b)a)2
=2|b|22(a.b)2+(a.b)2
=2|b|2(a.b)2
=2|b|sinθ
Area =12.3|b|sinθ.2|b|sinθ
=34(|b|4+4|)
|b|2sin2θ=14(|b|4+4)
4 sin2θ=|b|2+4|b|24
using AM GM
So equality holds because sin2θ=1
|b|4=4
|b|2=2

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