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Question

Let a=^i+^j+^k,b=^i^j+2^k and c=x^i+(x2)^j^k
If the vector c lies in the plane of a and b,then x=

A
1
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B
4
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C
2
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D
0
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Solution

The correct option is C 2
a,b,c are coplanar
[abc]=(a×b).c=0
∣ ∣111112x(x2)1∣ ∣
12(x2)(12x)+x2+x=0
2x+4=0 on simplification
x=2

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