Let p and q be any two logical statements and r be the statement p→(∼p∨q). If r has the truth value F, then the truth values of p and q are, respectively
A
F, F
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
T, T
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
F, T
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
T, F
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is DT, F pq∼p∼p∨qrTTFTTFFTTTTFFFFFTTTT
Clearly, from the above table, if r has the truth value F, then the truth values of p and q are T and F respectively.
Alternatively, a→b is false only when the truth value of a and b are T and F respectively. Given, p→(∼p∨q) is false. ⇒p is true and ∼p∨q is false. ⇒p is true and q is false.