Let P(n) : 2n<(1×2×3×....×n). Then the smallest positive integer for which P(n) is true is
1
2
3
4
(d) 4
Since,
P(1) : 2<1 is false
P(2) : 22<1×2 is false
P(3) : 23<1×2×3 is false
But P(4) : 24<1×2×3×4 is true.
Let P(n) denote the statement that n2 + n is odd. It
is seem that P(n) ⇒ P(n + 1), Pn is true for all