Let P(n) be the statement representing the sum of next three successive natural numbers of n, ∀n∈N, then the smallest value of n to which P(n) is divisible by 9 is
A
1
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B
3!
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C
3
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D
9!
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Solution
The correct option is A1 As p(n)=(n+1)+(n+2)+(n+3) p(n)=3n+3+3=3(n+2) ∴p(1)=3(3)=9 which is divisible by 9 ∴ least value of n is 1. Ans: A