Question

Let P(n) denote the statement that $n^2$ + n is odd. It

is seem that P(n) ⇒ P(n + 1), $P_n$ is true for all

• A. n > 1
• B. n
• C. n > 2
• D. None of these

Answer 1

The correct option is D

None of these

P(n) = $n^2$ + n. It is always odd (statement) but

square of any odd number is always odd and

also, sum of odd number is always even. So

for no any 'n' for which this statement is true.