Let P = {(x,y) x2+y2=1,x,y∈R}. Then P is.
Reflexive
Symmetric
Transitive
Anti-symmetric
Here we can see that the relation is neither reflexive nor transitive but it is symmetric,
because x2+y2=1⇒y2+x2=1
Let R be a relation on the set N be defined by {(x,y)|x,y|N,2x+y=41}. Then R is
Let R be a relation on the set N be defined by {(x, y)| x, y Î N, 2x + y = 41}. Then R is