Let P - x-y x2 - y2 - 1 - x - y - R - Then P is-

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Symmetric Relations

Let P = x,y x...

Question

Let P = {(x,y) $x^{2} + y^{2} = 1, x, y \in R}$ . Then P is.

Reflexive

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Symmetric

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Transitive

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Anti-symmetric

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Solution

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Similar questions

Let P = {(x,y) $x^{2} + y^{2} = 1, x, y \in R}$ . Then P is.

P = {(x, y) | x^{2} + y^{2} = 1, x, y \in R}

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R = {(P, Q) | P and Q are at the same distance from the origin}

(1, - 1)

P = {(x, y) | x^{2} + y^{2} = 1, x, y \in R}

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$P = {(x, y) : x, y ϵ R, x^{2} + y^{2} = 1}, t h e n P i s$

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