Given: R={(a,b):a,b∈N and a=b2}
If (a,b)∈R, then
a=b2 ...(1)
When (b,a)∈R
b=a2
From equation (1), we get
b=b4
⇒b(b3−1)=0
⇒b=0,1
As relation is defined from N to N, so b=1
So, (a,b)∈R⇒(b,a)∈R is not correct for all possible (a,b)∈R
Hence, the given statement is False.