Let R - x - y - x - y - Z - y -2 x -4- If p -2 and q 2-4 - R and pq -0- then the value of p -and q -

Given that nbsp;R=x,y: nbsp;x, nbsp;y nbsp;∈Z, nbsp;y= nbsp;2x 4.(p, nbsp; 2)∈R nbsp;⇒ 2=2p 4⇒2p=2⇒p=1(q2, nbsp;4)∈R⇒4=2q2 4⇒q2=4⇒q=±2Since, ...

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Standard XII

Mathematics

Definition of Relations

Let R = x , y...

Question

Let $R = ((x, y) : x, y \in Z, y = 2 x - 4} .$ If (p, -2) and $(q^{2}, 4) \in R$ and pq < 0 , then the value of p =
and q =

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Solution

Given that $R = ((x, y) : x, y \in Z, y = 2 x - 4} . (p, - 2) \in R \Rightarrow - 2 = 2 p - 4 \Rightarrow 2 p = 2 \Rightarrow p = 1 (q^{2}, 4) \in R \Rightarrow 4 = 2 q^{2} - 4 \Rightarrow q^{2} = 4 \Rightarrow q = \pm 2 Since, p and q are of opposite signs q = - 2$

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Q. Let

R = ((x, y) : x, y \in Z, y = 2 x - 4} .

If (p, -2) and

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Let R=((x,y): x, y ∈Z, y= 2x−4}. If (p, -2) and (q2, 4)∈R and pq < 0 , then the value of p = and q =

Given that R=((x,y): x, y ∈Z, y= 2x−4}.(p, −2)∈R ⇒−2=2p−4⇒2p=2⇒p=1(q2, 4)∈R⇒4=2q2−4⇒q2=4⇒q=±2Since, p and q are of opposite signs q=−2

Let $R = ((x, y) : x, y \in Z, y = 2 x - 4} .$ If (p, -2) and $(q^{2}, 4) \in R$ and pq < 0 , then the value of p =
and q =

Given that $R = ((x, y) : x, y \in Z, y = 2 x - 4} . (p, - 2) \in R \Rightarrow - 2 = 2 p - 4 \Rightarrow 2 p = 2 \Rightarrow p = 1 (q^{2}, 4) \in R \Rightarrow 4 = 2 q^{2} - 4 \Rightarrow q^{2} = 4 \Rightarrow q = \pm 2 Since, p and q are of opposite signs q = - 2$