Question

Let the least number of six digits, which when divided by 4, 6, 10 and 15, leaves in each case the same remainder of 2, be N. The sum of the digits in N is :

• A. 3
• B. 4
• C. 5
• D. 6
• E. 7

Answer 1

The correct option is C

5

Least number of 6 digits is 100000. L.C.M. of 4, 6, 10 and 15 = 60. On dividing 100000 by 60, the remainder obtained is 40.

$\therefore$ Least number of 6 digits divisible by 4, 6, 10 and 15 = 100000 + (60 - 40) = 100020.

$\therefore$ N = (100020 + 2) = 100022. Sum of digits in N = (1 +2 + 2) = 5.