Let the least number of six digits which when divided by $4, 6, 10$ and $15$ leaves in each case same remainder $2$ be $N .$ The sum of digits of $N$ is

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Solution

The correct option is A $3$
L.C.M of 4,6,10,15=60
Least number of 6 digits = 100000
on dividing 100000 by 60 the remainder 40
$∴$ Least number of 6 digits divisible by 4,6,10 & 15
100000+(60-40)=100020
$∴$ Required No = 100022 (100020+2)
Hence the sum of digits = 5

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Let the least number of six digits which when divided by 4,6,10 and 15 leaves in each case same remainder 2 be N. The sum of digits of N is

The correct option is A 3L.C.M of 4,6,10,15=60Least number of 6 digits = 100000on dividing 100000 by 60 the remainder 40∴ Least number of 6 digits divisible by 4,6,10 & 15100000+(60-40)=100020∴ Required No = 100022 (100020+2)Hence the sum of digits = 5

Let the least number of six digits which when divided by $4, 6, 10$ and $15$ leaves in each case same remainder $2$ be $N .$ The sum of digits of $N$ is

The correct option is A $3$
L.C.M of 4,6,10,15=60
Least number of 6 digits = 100000
on dividing 100000 by 60 the remainder 40
$∴$ Least number of 6 digits divisible by 4,6,10 & 15
100000+(60-40)=100020
$∴$ Required No = 100022 (100020+2)
Hence the sum of digits = 5