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Question

Let the matrix M=100101010 satisfy Mn=Mn2+M2I for n=3,4,5,6, where I is the identity matrix of order 3.
Also U1,U2,U3 are column matrices satisfying M50U1=12525,M50U2=010,M50U3=001 and U is a 3×3 matrix whose columns are U1,U2,U3.
Then

A
M50=25M224I
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B
det(adj M50) is equal to 1
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C
Let X=xyz and B=024 be two matrices. Then the system of equations UX=B has infinitely many solutions.
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D
Let X=xyz and B=024 be two matrices. Then the system of equations UX=B has a unique solution.
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Solution

The correct option is D Let X=xyz and B=024 be two matrices. Then the system of equations UX=B has a unique solution.
M50=M48+M2I
Further, M48=M46+M2I
M48=M46+M2I

M6=M4+M2I
M4=M2+M2I
Adding the above equations, we get
M50=25M224I

Here, M2=MM=100101010100101010=100110101
M50=2500252502502524100010001
M50=10025102501
det(M50)=1
det(adj M50)=(det(M50))31=1

Here, matrix U=100010001
det(U)=10
The system of equations UX=B has a unique solution.

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