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Byju's Answer

Standard XII

Physics

Validating the Bohr's Model

Let u 1 be th...

Question

Let $u_{1}$ be the frequency of the series limit of the Lyman series, $u_{2}$ be the frequency of the first line of the Lyman series, and $u_{3}$ be the frequency of the series limit of the Balmer series. Then-

u_{1} - u_{2} = u_{3}

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u_{2} - u_{1} = u_{3}

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u_{3} = \frac{1}{2} (u_{2} + u_{1})

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u_{3} = (u_{2} + u_{1})

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Solution

The correct option is A $u_{1} - u_{2} = u_{3}$
$u_{1} = R (\frac{1}{1^{2}} - \frac{1}{\infty}); u_{2} = R (\frac{1}{1^{2}} - \frac{1}{2^{2}}); u_{3} = R (\frac{1}{2^{2}} - \frac{1}{\infty}); H e n c e u_{1} - u_{3} = u_{2}$

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Similar questions

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Q. Let

A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 0 & 0 2 & 1 & 0 3 & 2 & 1 \end{matrix} ⎤ ⎥ ⎦

and

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| U | =

Let $v_{1}$ be the frequency of the series limit of the Lyman series, $v_{2}$ be the frequency of the first line of Lyman series, and $v_{3}$ be the frequency of the series limit of Balmer series. Then

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Let u1 be the frequency of the series limit of the Lyman series, u2 be the frequency of the first line of the Lyman series, and u3 be the frequency of the series limit of the Balmer series. Then-

The correct option is A u1−u2=u3u1=R(112−1∞); u2=R(112−122); u3=R(122−1∞); Hence u1−u3=u2

Let $u_{1}$ be the frequency of the series limit of the Lyman series, $u_{2}$ be the frequency of the first line of the Lyman series, and $u_{3}$ be the frequency of the series limit of the Balmer series. Then-

The correct option is A $u_{1} - u_{2} = u_{3}$
$u_{1} = R (\frac{1}{1^{2}} - \frac{1}{\infty}); u_{2} = R (\frac{1}{1^{2}} - \frac{1}{2^{2}}); u_{3} = R (\frac{1}{2^{2}} - \frac{1}{\infty}); H e n c e u_{1} - u_{3} = u_{2}$