Let →a=2^i+^j−3^k,→b=^i+3^j+2^k. Then the volume of the parallelopipied having coterminous edges as →a,→b and →c where →c is the vector perpendicular to the plane of →a,→b and |→c|=2
A
2√195
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B
24
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C
√200
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D
√195
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Solution
The correct option is A2√195
Given vectors are ^a=2→i+→j−3→k,^b=→i+3→j+2→k
Also given |^c|=2
We know [→a→b→c]=∣∣→a×→b∣∣|→c|cosθ =∣∣11→i−7→j+5→k∣∣×2