Let A-2-3k- B-4-2- C-2-2-2k- Then the ratio in which C divides AB is

The correct option is A 1:2 Let A=(1,2,3) , #160; B=(4,2,0) and C=(2,2,2) Now let C divide the line joining BA in the ration ...

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Section Formula

Let A⃗=î+2ĵ...

Question

Let $\to A =^i + 2^j + 3^k, \to B = 4^i + 2^j, \to C = 2^i + 2^j + 2^k$ . Then the ratio in which $C$ divides $A B$ is

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\to a = 3^i - 2^j +^k,

\to b = 2^i - 4^j - 3^k, \to c = -^i + 2^j + 2^k

\to a + \to b + \to c = 4^i - 4^j

\to a =^i -^j + 2^k, \to b = 2^i + 3^j +^k, \to c =^i -^k

\to a + 2 \to b - 3 \to c

\sqrt{78}

\to a = 3^i - 2^j +^k, \to b = 2^i - 4^j - 3^k

\to c = - 1^i + 2^j + 2^k

\to a + \to b + \to c =

\to a = 2^i +^j +^k

\to b =^i + 2^j + 2^k

\to c =^i +^j + 2^k

\to a \times (\to b \times \to c) = (1 + α)^i + β (1 + α)^j + r (1 + α) (1 + β)^k

\to a = 2^i +^j + 3^k

\to b = 3^i + 2^j +^k

\to c =^i -^j - 4^k

\to d =^i + 2^j -^k

(\to a \times \to b) \times (\to c \times \to d) =

\to A = 2^i + 7^j, \to B =^i + 2^j + 4^k, \to C = \frac{9^i + 30^j + 4^k}{5}

\to C

\to A B

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