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Question

Let a=^i+^j, b=2^i^k. Then the point of intersection of the lines ^r×a=b×a and ^r×b=a×b is

A
3^i+^j^k
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B
3^i^j^k
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C
3^i3^j^k
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D
3^i+3^j+^k
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Solution

The correct option is A 3^i+^j^k
We have
a=ˆi+ˆj
b=2ˆiˆk
The point of intersection of line r×a=b×a
(rb)×a=0
rb=ta
r=b+ta
Again the points of intersection of line r×b=a×b
(ra)×b=0
ra=λb
r=a+λb

From the Both of line we get
λ=1t=1

The of the points of the intersection of the both given line
r=a+b
=3ˆi+ˆjˆk
Hence, the option A is the correct answer.

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