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Question

Let x1,x2,x3,x4 and x5 be roots of p(x)=x5+x2+1 and g(x)=x22. The value of g(x1)g(x2)g(x3)g(x4)g(x5)30g(x1x2x3x4x5) is___

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Solution

x1x2x3x4x5=1g(x1x2x4x5)=12=1
Let y=g(x)x=y+2
Substitute in p(x)(y+2)52=(y+3)
y5+104+40y3+79y2+74y+23=0
Roots are:g(xi),p=1 to 5
g(x1)g(x2)g(x3)g(x4)g(x5)=232330(1)=7

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