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Standard X

Mathematics

Geometric Mean

Let x bar be ...

Question

Let x bar be the mean of x1,x2,....x2n and y bar be the
Meanof y1,y2,...y 2n then z bar=

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Solution

So z bar is the mean of Z1,Z2,Z3......
i think something is missing in the question

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Similar questions

Q. Let

¯ x

be the mean of

x_{1}, x_{2}, . . ., x_{n}

and

¯ y

the mean of

y_{1}, y_{2}, . . ., y_{n}

. If

¯ z

is the mean of

x_{1}, x_{2}, . . ., x_{n}

y_{1}, y_{2}, . . ., y_{n}

, then

¯ z

is equal to

Q. Let

x

be the mean of

x_{1}, x_{2}, . . ., x_{n}

and

y

be the mean of

y_{1}, y_{2}, . . ., y_{n}

.
If

z

is the mean of

x_{1}, x_{2}, . . ., x_{n}, y_{1}, y_{2}, . . ., y_{n},

then

z = ?

(a)

(x + y)

(b)

\frac{1}{2} (x + y)

(c)

\frac{1}{n} (x + y)

(d)

\frac{1}{2 n} (x + y)

Q. Let

\bar{X}

be the mean of x₁,x₂,...,x_n, and

\bar{Y}

the mean of y₁,y₂,...,y_n, if

\bar{Z}

is the mean of x₁,x₂,...,x_n, y₁,y₂,...,y_n, then

\bar{Z}

is equal to

(a) \bar{X} + \bar{Y} (b) \frac{\bar{X} + \bar{Y}}{2} (c) \frac{\bar{X} + \bar{Y}}{n} (d) \frac{\bar{X} + \bar{Y}}{2 n}

Q. Question 15
Let

¯ x

be the mean of

x_{1}, x_{2}, \dots \dots x_{n}

, and

¯ y

be the mean of

y_{1}, y_{2}, \dots \dots y_{n}

. If

¯ z

represents the mean of

x_{1}, x_{2}, \dots \dots x_{n}, y_{1}, y_{2}, \dots \dots y_{n}

, then

¯ z

is equal to:

A)

¯ x + ¯ y

\frac{¯ x + ¯ y}{2}

\frac{¯ x + ¯ y}{n}

\frac{¯ x + ¯ y}{2 n}

Let $¯ x$ be the mean of $x_{1}, x_{2}, \dots, x_{n}$ . and $¯ y$ be the mean of $y_{1}, y_{2} \dots, y_{n}$ If $¯ z$ is the mean of $x_{1}, x_{2}, \dots, x_{n}, y_{1}, y_{2}, \dots y_{n}$ , then $¯ z = ?$

(a) $(¯ x + ¯ y)$

(b) $\frac{1}{2} (¯ x + ¯ y)$

(b) $\frac{1}{2 n} (¯ x + ¯ y)$

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Let x bar be the mean of x1,x2,....x2n and y bar be the Meanof y1,y2,...y 2n then z bar=

So z bar is the mean of Z1,Z2,Z3...... i think something is missing in the question

Let x bar be the mean of x1,x2,....x2n and y bar be the
Meanof y1,y2,...y 2n then z bar=

So z bar is the mean of Z1,Z2,Z3......
i think something is missing in the question