Let x -4-4-4-4- Then- x equalsA- 13B- -13-1-2C- -13-1-2D- -13

The correct option is C √(13)+1/2Option (C) is the correct answer. Check the video for the approach. ...

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Quadratic Equations

Let x =√4+√4-...

Question

Let $x = \sqrt{4 + \sqrt{4 - \sqrt{4 + \sqrt{4 - . . . . \infty}}}}$ . Then, x equals

13

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\frac{\sqrt{13} - 1}{2}

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\frac{\sqrt{13} + 1}{2}

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\sqrt{13}

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x = \sqrt{4 + \sqrt{4 - x}}

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The possible values of expression $\frac{1}{x^{2} - x - 3}$ is

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\frac{4}{3} \times [x + \frac{1}{13}] = \frac{4}{3} \times \frac{8}{11} + \frac{4}{3} \times \frac{1}{13} .

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