Let x(t) be a continuous-time, real -valued signal band-limited to F Hz. The Nyquist sampling rate in Hz for y(t) = x(0.5 t) + x(t) - x(2t) is

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4 F

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Solution

The correct option is C 4 F
Expansion in time domain is compressed in frequency domain and vice-versa. So, the maximum frequency component in given signal is 2 F Hz. and according to sampling theorem

$Nyquist rate = 2 f_{m} = 2 \times 2 F = 4 F H z$

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