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Question

Let x+y being acute and if sinx.cosy+cosx.siny=0 then the value of sinx+siny=

A
1
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B
1
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C
0
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D
none of these
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Solution

The correct option is C 0
Given,
sinx.cosy+cosx.siny=0
or, sin(x+y)=0
or, x+y=0.....(1). [ As x+y being acute]
Now,
sinx+siny
=sinx+sin(x) [ Using (1)]
=sinxsinx
=0.

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