Question

Let $y=x^{10}+{10}^x+10$ then find $\frac{dy}{dx}$

Answer 1

Given,

$y=x^{10}+{10}^x+10$.

Now differentiating both sides with respect to $x$ we get,

$\frac{dy}{dx}=10x^{10-1}+{10}^x.{\log }_{e}10+0$

or, $\frac{dy}{dx}=10x^9+{10}^x.{\log }_{e}10$.