Question

Let $y=x^2-2x+1$ then find the value of $y$ for which $\frac{dy}{dx}=-2$.

Answer 1

Given,

$y=x^2-2x+1$

Now differentiating both sides we get,

$\frac{dy}{dx}=2x-2$.

Now $\frac{dy}{dx}=-2$

Gives $x=0$.

For $x=0$, $y=1$.