Let z1-1-i and z2-1-i then find z1z2-

Given #160; z_1=(1+i) and z_2=(1 i) . #160;Then #160; z_1z_2 =(1+i)1 i) =(1+i)^21^2 i^2 =2i2 =i . ...

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Algebra of Complex Numbers

Let z1=1+i ...

Question

Let $z_{1} = (1 + i)$ and $z_{2} = (1 - i)$ then find $\frac{z_{1}}{z_{2}}$ .

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z_{1} = (2 - i)

z_{2} = (1 + i),

∣ ∣ ∣ \frac{z_{1} + z_{2} + 1}{z_{1} - z_{2} + i} ∣ ∣ ∣

z_{1} = (2 - i)

z_{2} = (1 + i),

∣ ∣ ∣ \frac{z_{1} + z_{2} + 1}{z_{1} - z_{2} + i} ∣ ∣ ∣

z_{1} = 2 - i, z_{2} = 1 + i

∣ ∣ ∣ \frac{z_{1} + z_{2} + 1}{z_{1} + z_{2} + i} ∣ ∣ ∣

z_{1} = 1 - i

z_{2} = \sqrt{3} + i

z_{1} \cdot z_{2}

If $z_{1} = 2 - i$ and $z_{2} = 1 + i$ , find $∣ ∣ \frac{z_{1} + z_{2} + 1}{z_{1} - z_{2} + 1} ∣ ∣$

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