Let z,w be complex numbers such that ¯¯¯z+i¯¯¯¯w=0 and arg zw=π. Then arg z equals
A
π4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
π2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3π4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
5π4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C3π4 Let z=cosA+isinA and w=cosB+isinB ¯¯¯z=cosA−isinA and ¯¯¯¯w=cosB−isinB zw=cos(A+B)+isin(A+B) ¯¯¯z+i¯¯¯¯w =cosA+sinB+i(cosB−sinA) Now cosA+sinB=0 and cosB−sinA=0 And A+B=π A=π−B cos(B)=sin(π−B) cos(B)=sin(B) Therefore arg(Z) =π−π4 =3π4