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Question

Let z,w be complex numbers such that ¯¯¯z+i¯¯¯¯w=0 and arg zw=π. Then arg z equals

A
π4
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B
π2
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C
3π4
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D
5π4
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Solution

The correct option is C 3π4
Let
z=cosA+isinA and w=cosB+isinB
¯¯¯z=cosAisinA and ¯¯¯¯w=cosBisinB
zw=cos(A+B)+isin(A+B)
¯¯¯z+i¯¯¯¯w
=cosA+sinB+i(cosBsinA)
Now cosA+sinB=0 and cosBsinA=0
And A+B=π
A=πB
cos(B)=sin(πB)
cos(B)=sin(B)
Therefore arg(Z)
=ππ4
=3π4

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