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Question

lf ex(1+x)sec2(xex)dx=f(x)+c, then f(x)=

A
cos(xex)
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B
sin(xex)
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C
2tan1(x)
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D
tan(xex)
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Solution

The correct option is C tan(xex)
Substitute xex=t
ex(1+x)dx=dt
sec2tdt=Tant+c
=tan(xex)+c
Hence, f(x)=tan(xex)

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