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Question

lf y=(x+1+x2)m, then (1+x2)y2+xy1m2y=

A
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B
1
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C
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Solution

The correct option is B 0
y=(x+1+x2)m
differentiating y with respect to x
y1=m(x+1+x2)m1(1+x1+x2)
y1=m(x+1+x2)m1x+1+x21+x2
y1=m(x+1+x2)m11+x2=my1+x2
y11+x2=my
differentiating both side with respect to x
y21+x2+xy11+x2=my1
y2(1+x2)+xy1=my11+x2=m2y
y2(1+x2)+xy1m2y=0

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