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B
1
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C
−1
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D
2
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Solution
The correct option is B0 y=(x+√1+x2)m differentiating y with respect to x y1=m(x+√1+x2)m−1(1+x√1+x2) ⟹y1=m(x+√1+x2)m−1x+√1+x2√1+x2 ⟹y1=m(x+√1+x2)m∗1√1+x2=my√1+x2 ⟹y1√1+x2=my differentiating both side with respect to x y2√1+x2+xy1√1+x2=my1 ⟹y2(1+x2)+xy1=my1√1+x2=m2y ⟹y2(1+x2)+xy1−m2y=0