The correct option is D None of the above is even
Case I
If n is odd, then n+1 will be even. This implies,
(n)(n+1) will be even. ...(since (n+1) is even).
Therefore the expression (n)(n+1)+1 will be odd ...(even no. +1).
Case II
If n is even, then n+1 will be odd. This implies,
(n)(n+1) will be even. ...(since (n) is even).
Therefore the expression (n)(n+1)+1 will be odd ...(even no. +1).
Hence for all nϵN the n(n+1)+1 is odd.