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Question

lf P(n) be the statement n(n+1),nN is even, then

A
P(2) is true
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B
P(3) is true
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C
P(4) is true
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D
all of the above
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Solution

The correct option is D all of the above
Case 1. If n is even n+1 will be an odd
Thus P(n)=n(n+1)= even × odd =even
Case 2. If n is odd n+1 will be an even
Thus P(n)=n(n+1)= odd × even =even
Hence P(n) is an even number for all nN
In particular P(2),P(3),P(4) are even

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