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B
P(3) is true
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C
P(4) is true
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D
all of the above
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Solution
The correct option is D all of the above Case 1. If n is even ⇒n+1 will be an odd Thus P(n)=n(n+1)= even × odd =even Case 2. If n is odd ⇒n+1 will be an even Thus P(n)=n(n+1)= odd × even =even Hence P(n) is an even number for all n∈N In particular P(2),P(3),P(4) are even