CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

lf the roots of the equation ax2+bx+c=0 are the reciprocals of the roots of the equation px2+qx+r=0, then

A
acq2=b2pr
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
ac=pr
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
b2ac=q2pr
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
ab=pq
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A acq2=b2pr
Letα,βbetherootsofthegivenequationax2+bx+c=0α+β=ba....(1)andαβ=ca.....(2)Nowtheequationhavingroots1α,1βwillbex2(1α+1β)x+1αβ=0x2α+βαβx+1αβ=0Substitutingforα+βandαβfromequations(1)and(2),weget,x2bacax+1ca=0x2+bcx+ac=0cx2+bx+a=0Thisequationisidenticalwithpx2+qx+r=0comparingthecoefficientsofx2,xandcwehave,cp=bq=arcp×ar=bq×bq[bothcpandarareequaltobq]acq2=b2prAnsOptionA.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relation of Roots and Coefficients
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon