lf (u,v,w) be the centre of the sphere which passes through the points (0,0,0),(0,2,0),(1,0,0) and(0,0,4), then u+v+w=
A
32
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B
52
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C
72
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D
92
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Solution
The correct option is C72 Equation of sphere passes through origin is given by, x2+y2+z2+ax+by+cz=0 Given, it also passes through (0,2,0),(1,0,0),(0,0,4) 4++2b=0⇒b=−2 1+a=0⇒a=−1 and 16+4c=0⇒c=−4 Therefore, the centre of the sphere is (12,1,2) Ergo u+v+w=72