Question

$L{i}^{2+}$ ion is in the excited state with wave function of its electron being denoted by the symbol ${\Psi }_{3,1,0}$. How many radiations of different wavelength will this $L{i}^{2+}$ ion will emit upon de-excitation?

• A. zero
• B. 6
• C. 3
• D. 1

Answer 1

The correct option is C 3

As presently electron is in 2rd excited state $n=3$.
When it de-excite, total no. of radiations $=n\times (n-1)/2=3\times (3-1)/2=3$.