$L i A l H_{4}$ converts acetic acid into

Acetaldehyde

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Methane

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Ethyl alcohol

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Methyl alcohol

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Solution

The correct option is C Ethyl alcohol
$C H_{3} C O O H + 4 H L i A l H_{4} - --- \to C H_{3} C H_{2} O H + H_{2} O$

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