$L i A l H_{4}$
Find oxidation no.of $A l$ .

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Solution

${L i A l H}_{4} \to {L i}^{+} + {[{A l H}_{4}]}^{-}$
${[{A l H}_{4}]}^{-} \Rightarrow x + (4) (- 1) = - 1$
$∴ x - 4 = - 1$
$∴ x = + 3$
Therefore, oxidation number of $A l$ is $+ 3$ .

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