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Question

Light of wavelength 600ηm is incident normally on a slit of width 0.2mm. The angular width of central maxima in the diffraction pattern is :
(measured from minimum to minimum)

A
6×103rad
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B
4×103rad
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C
2.4×103rad
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D
4.5×103rad
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Solution

The correct option is B 6×103rad
Given : λ=600nm=6×107 m b=0.2mm=0.2×103
Angular width of first minima from central maxima in diffraction pattern θ=λd
Angular width of central maxima, θc=2θ=2λd
θc=2×6×1070.2×103=6×103 rad

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