Light of wavelength λshines on a metal surface with intensity X, the metal emits Y electrons per second of average energy Z. If X is doubled, Y
In photoelectric effect:
→ The number of electrons ejected are proportional to intensity of light
→ Intensity does not affect average energy of photo-electrons.
Now, when intensity is doubled, the number of electrons emitted per second (Y) will be doubled.
Further - there will be no effect on the average energy of photo-electrons (Z).
⇒ Y → Doubled
Z → Same