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Question

Light of wavelength λshines on a metal surface with intensity X, the metal emits Y electrons per second of average energy Z. If X is doubled, Y , Z

A
halved
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B
remains same
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C
doubles
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D
quadruples
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Solution

The correct option is C doubles

In photoelectric effect:

The number of electrons ejected are proportional to intensity of light

Intensity does not affect average energy of photo-electrons.

Now, when intensity is doubled, the number of electrons emitted per second (Y) will be doubled.
Further - there will be no effect on the average energy of photo-electrons (Z).

Y Doubled

Z Same


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