LiH+B2H6EtherāāāāA. A is as follows
LiBH
LiBH2
LiBH4
None of these
Diborane when treated with lithium hydride forms Lithium borhydride.
LiH+B2H6Ether−−−→LiBH4
LiH+B2H6Ether−−−→A. A is as follows
Look at the following reaction: LiH+AlH3⟶LiAlH4 Here AlH3 and LiH act as:
BF3+LiH→A+LiBF4. A is as follows