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Question

LiH+B2H6Etherāˆ’āˆ’āˆ’ā†’A. A is as follows


A

LiBH

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B

LiBH2

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C

LiBH4

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D

None of these

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Solution

The correct option is C

LiBH4


Diborane when treated with lithium hydride forms Lithium borhydride.

LiH+B2H6Ether−−LiBH4


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