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B
asina+a2cosa
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C
2asina+a2cosa
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D
2acosa+a2sina
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Solution
The correct option is C2asina+a2cosa dda[a2sina]=2asina+a2cosa Aliter: Apply L - Hospital's rule, limh→0(a+h)2sin(a+h)−a2sinah =limh→02(a+h)sin(a+h)+(a+h)2cos(a+h)1 =2asina+a2cosa