${lim}_{x \to 0} \frac{3^{2 + x} - 9}{x}$

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Solution

${lim}_{x \to 0} \frac{3^{2 + x} - 9}{x} = {lim}_{x \to 0} \frac{3^{2} . 3^{x} - 9}{x} = 9 {lim}_{x \to 0} \frac{3^{x} - 1}{x} = 9 {log}_{e} 3$

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