CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

limx021+cosxx2

Open in App
Solution

limx021+cosxx2

=limx022cos2x2x2

=limx02(1cosx2)x2

=limx02(2sin2x4)x2

=22limx0(sinx4x4)2×116

[limx0sinθθ=1]

=22×116=142


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Standard Expansions and Standard Limits
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon