limx→π21−sinxcos2x
limx→π21−sinxcos2x =limx→x21−sinx1−sin2x=limx→x2(1−sinx)(1−sinx)(1+sinx) =limx→x211+sinx=11+sinπ2 =11+1=12
limx→π2√2−√1+sin xcos2 x
Find the value of limx→π4cos x−sin xcos 2 x