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B
NaOH
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C
H2O2
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D
all
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Solution
The correct option is BAs2S3 Initial mmoles of As2S3=0.4×100=40 Initial mmoles of NaOH=5×100=500 Initial mmoles of H2O2=6×100=600 Balanced equation shows that As2S3 is the limiting reagent. As2S3+12⊝OH+14H2O2→2AsO3−4+3SO2−4+20H2O