Question

Limiting value of equivalent conductance of $BaS{O}_4$, $BaC{l}_2$ and $H_{2}S{O}_4$ are $X,Y$ and $Z$ respectively. Equivalent conductance of $HCl$ at infinite dilution is:

• A. $Y+Z-X$
• B. $1/2(X+Y-Z)$
• C. $1/2(Z+X-Y)$
• D. $1/2(Y+Z-X)$

Answer 1

The correct option is D $1/2(Y+Z-X)$

$H_{2}S{O}_4+BaC{l}_2⟶2HCl+BaS{O}_4$

$\therefore {\wedge }_{m_{HCl}}=\frac{1}{2}[{\wedge }_{m_{H_{2}S{O}_4}}+{\wedge }_{m_{BaC{l}_2}}-{\wedge }_{m_{BaS{O}_4}}]$

${\wedge }_{m_{HCl}}=\frac{1}{2}[Z+Y-X]$