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Question

# Lina is three times as old as Paul. If the sum of their ages is 48, find their respective ages.

A
Age of Paul is 22.5 years and age of Lina is 25.5 years.
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B
Age of Paul is 12 years and age of Lina is 36 years.
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C
Age of Paul is 36 years and age of Lina is 12 years.
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Solution

## The correct option is B Age of Paul is 12 years and age of Lina is 36 years.Let Paul's age be x years. Lina is 3 times as old as Paul. ∴ Lina's age = 3×x=3x years Algebraic expression of Lina's age is 3x. It is given that the sum of their age is 48. ∴3x+x=48 ⇒4x=48 To undo the multiplication we divide the both side of the equation by 4. 4x=48 ⇒4×x4=484 ⇒x=12 ∴ Paul's age is 12 years. ⇒Lina's age =3x=3×12=36 years To verify this we add their ages and check if we get 48 as the sum. 36+12=48 Hence, the results are correct.

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