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Standard XII

Chemistry

First Law of Thermodynamics

Linear densit...

Question

Linear density of a string is $1.3 \times 10^{- 4} k g / m$ and wave equation is $y = 0.021 sin (x + 30 t)$ . Find the tension in the string where $x$ in metre and $t$ in second :

0.12 N

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0.21 N

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1.2 N

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0.012 N

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Solution

The correct option is A 0.12 N
Velocity of wave $v = \frac{c o - e f f i c i e n t o f t}{c o - e f f i c i e n t o f x} = \frac{30}{1} = 30 m / s$
Using $v^{2} = \frac{T}{μ}$
Or $30^{2} = \frac{T}{1.3 \times 10^{- 4}}$
$⟹ T = 0.12 N$

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Linear density of a string is 1.3×10−4kg/m and wave equation is y=0.021sin(x+30t). Find the tension in the string where x in metre and t in second :

The correct option is A 0.12 NVelocity of wave v=co−efficient of tco−efficient of x=301=30 m/sUsing v2=TμOr 302=T1.3×10−4⟹ T=0.12 N

Linear density of a string is $1.3 \times 10^{- 4} k g / m$ and wave equation is $y = 0.021 sin (x + 30 t)$ . Find the tension in the string where $x$ in metre and $t$ in second :

The correct option is A 0.12 N
Velocity of wave $v = \frac{c o - e f f i c i e n t o f t}{c o - e f f i c i e n t o f x} = \frac{30}{1} = 30 m / s$
Using $v^{2} = \frac{T}{μ}$
Or $30^{2} = \frac{T}{1.3 \times 10^{- 4}}$
$⟹ T = 0.12 N$