Lines AB and CD intersect at point O. If ∠AOC + ∠BOE = 100° , find ∠COE.
60°
50°
80°
40°
AB is a straight line, so sum of all the angles at 'O' above the line is 180∘
i.e. ∠AOC + ∠COE + ∠EOB = 180∘
or, ∠COE = 180∘ - (∠AOC + ∠BOE)
or, ∠COE = 80∘
In the figure below, lines AB and CD intersect at O. If ∠AOC + ∠BOE = 70∘ and ∠BOD = 40∘, find 2∠BOE.
In the figure below, lines AB and CD intersect at O. If ∠AOC+∠BOE=70∘ and ∠BOD=40∘, find (2∠BOE).
In the figure below, lines AB and CD intersect at O. If ∠AOC + ∠BOE = 70∘ and ∠BOD = 40∘, find (3∠BOE).
In the figure below, lines AB and CD intersect at O. If ∠AOC + ∠BOE = 70∘ and ∠BOD = 40∘, find (2∠BOE).